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Question: At 27°C one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm ...

At 27°C one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. The values of ∆E and q are (R = 2)

A

0, –965.84 cal

B

– 965.84 cal, + 965.84 cal

C
  • 865.58 cal, –865.58 cal
D

–865.58 cal, –865.58 cal

Answer

0, –965.84 cal

Explanation

Solution

w=2.303nRTlogP1P2w = - 2.303nRT\log\frac{P_{1}}{P_{2}}

=2.303×1×2×300log210=965.84\mathbf{= 2.303}\mathbf{\times}\mathbf{1}\mathbf{\times}\mathbf{2}\mathbf{\times}\mathbf{300}\mathbf{\log}\frac{\mathbf{2}}{\mathbf{10}}\mathbf{= 965.84}

At constant temperature ΔE=0\Delta E = 0

ΔE=q+w\Delta E = q + w; q=w=965.84calq = - w = - 965.84cal