Question
Question: At 25<sup>0</sup>C, the solubility product of Mg(OH)2 is 1.0 ´ 10–11. At Which pH, will Mg2+ ions st...
At 250C, the solubility product of Mg(OH)2 is 1.0 ´ 10–11. At Which pH, will Mg2+ ions start precipitating in the form of Mg(OH)2 from a solution of 0.001 M Mg2+ ions ?
A
9
B
10
C
11
D
8
Answer
10
Explanation
Solution
KSP = 1.0 × 10–11 = (Mg+2) (OH–)2
1.0 × 10–11 = (0.001) (OH–)2
(OH–) = 10–4
POH = 4
PH = 14 – 4 = 10.