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Question: Assuming the sun to be a spherical body of radius \(R\) at a temperature of \(T\,K\). Evaluate the i...

Assuming the sun to be a spherical body of radius RR at a temperature of TKT\,K. Evaluate the intensity of radiant power, incident on Earth, at a distance rr from the sun where r0{r_0} is the radius of the earth and σ\sigma is Stefan’s constant:
(A) R2σT4r2\dfrac{{{R^2}\sigma {T^4}}}{{{r^2}}}
(B) 4π2R2σT4r2\dfrac{{4{\pi ^2}{R^2}\sigma {T^4}}}{{{r^2}}}
(C) π2R2σT4r2\dfrac{{{\pi ^2}{R^2}\sigma {T^4}}}{{{r^2}}}
(D) π2R2σT44πr2\dfrac{{{\pi ^2}{R^2}\sigma {T^4}}}{{4\pi {r^2}}}

Explanation

Solution

Sun is assumed to be a black body which continuously emits energy. Hence use Stefan’s formula to calculate the energy emitted by the sun per second. With the help of that answer, find the energy received by the earth by substituting the given or assumed details.

Formulae Used:
(1) By the Stefan’s law of black body,
P=σAT4P = \sigma A{T^4}
Where P is the energy of radiant power emitted by the sun per second, AA is the total area of the sun, σ\sigma is the stefan- Boltzmann constant which is equal to 1.714×1091.714 \times {10^{ - 9}} and TT is the temperature of the sun.
(2) Area of the circle
A=4πR2A = 4\pi {R^2}
Where RR is the radius of the sun.
(3) Energy received by the earth
PE=Ia{P_E} = Ia
Where PE{P_E} is the energy received by the earth, II is the intensity of the energy received by the earth and aa is the area of the Earth.

Complete step-by-step solution:
The assumed data from the question are
Sun is assumed to be a spherical body of the radius, RR
Distance between the sun and the earth, rr
Radius of the earth, r0{r_0}
Assuming the sun as the spherical black body, Stefan’s law is applicable to it.

P=σAT4P = \sigma A{T^4}
Substituting the formula for area in the above equation
P=4σπR2T4P = 4\sigma \pi {R^2}{T^4}………………(1)
Since the sun is far away from the Earth, rr0r \gg {r_0}
Intensity of the sun at the Earth is obtained by dividing the total intensity emitted by the sun per second by the area to which it emits.
I=PAI = \dfrac{P}{A}
Substituting the equation (1) in the above equation.
I=4σπR2T24πr2I = \dfrac{{4\sigma \pi {R^2}{T^2}}}{{4\pi {r^2}}}
By simplifying the above equation.
I=σR2T2r2I = \dfrac{{\sigma {R^2}{T^2}}}{{{r^2}}}………………………(2)
To calculate the total radiant power emitted by the sun to the earth surface,
PE=Ia{P_E} = Ia
Substituting (2) in the above formula. Assuming the Earth to be a round body, hence its area is πr2\pi {r^2}
PE=σR2T2×πr02r2{P_E} = \dfrac{{\sigma {R^2}{T^2} \times \pi r_0^2}}{{{r^2}}}
Thus the option (B) is correct.

Note:- Remember that the sun is assumed to be spherical so its area is taken as 4πR24\pi {R^2} and Earth is assumed to be in disc shaped and hence its area is taken as πr02\pi r_0^2. Care must be taken in simplifying and substituting the formulae given.