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Question: Assuming the olivine series of minerals consists of crystal in which \[F{e^{2 + }}\] and \[M{g^{2 + ...

Assuming the olivine series of minerals consists of crystal in which Fe2+F{e^{2 + }} and Mg2+M{g^{2 + }} ions may substitute for each other causing substitutional impurity defect without changing the volume of the unit cell. In the olivine series of minerals, oxide ion exits as fcc with Si4+S{i^{4 + }}occupying 14th\dfrac{1}{4}th of octahedral void and divalent ion occupying 14th\dfrac{1}{4}th of the tetrahedral void. The density of Forsterite (Magnesium silicate) is 3.21gcc3.21\dfrac{g}{{cc}} and that of Fayalite (Ferrous Silicate) is4.34gcc4.34\dfrac{g}{{cc}}. If the density of olivine is3.88gcc3.88\dfrac{g}{{cc}}, then which of the following statements is /are correct?
A. Olivine contains 40.71%40.71\% Forsterite and 59.29%59.29\% Fayalite.
B. Fayalite is Fe2SiO4F{e_2}Si{O_4}and Forsterite isMgSiO4MgSi{O_4}.
C. Percentage of ForsteriteMgSiO4MgSi{O_4}is59.2959.29.
D. Both options A and B.

Explanation

Solution

Hint : Chemical composition of olivine falls somewhere close to pure Forsterite (MgSiO4MgSi{O_4}) and pure Fayalite(Fe2SiO4F{e_2}Si{O_4}). Around there MgMgand can elective uninhibitedly for one another in the mineral’s nuclear design-in any proportion, known as “solid arrangement”.

Complete step-by-step solution:
According to the question we get-
Number of O2{O^{ - 2}}atoms

=8×18+6×12 =1+3 =4  = 8 \times \dfrac{1}{8} + 6 \times \dfrac{1}{2} \\\ = 1 + 3 \\\ = 4 \\\

Number of Si4+S{i^{4 + }}atoms =14×= \dfrac{1}{4} \timesoctahedral void

=14×4 =1  = \dfrac{1}{4} \times 4 \\\ = 1 \\\

Number of Mg2+M{g^{2 + }} atoms 14×\dfrac{1}{4} \times tetrahedral void

=14×8 =2  = \dfrac{1}{4} \times 8 \\\ = 2 \\\

We know the formula of Forsterite =MgSiO4 = MgSi{O_4} and Fayallite=Fe2SiO4 = F{e_2}Si{O_4}
Let us assume the Forterite is x%x\% and Fayalite is (100x)%(100 - x)\%
Therefore,

x×3.21+(100x)×4.34100=3.88 x=40.71%Forsterite   \dfrac{{x \times 3.21 + (100 - x) \times 4.34}}{{100}} = 3.88 \\\ \therefore x = 40.71\% - Forsterite \\\ \\\

And the percentage of Fayalite (10040.71)=59.29\left( {100 - 40.71} \right) = 59.29.
Therefore, the right option is D.

Note: Olivine has additionally been utilized as a hard–headed material. It is utilized to make a headstrong block and utilized as projecting sand. It is the primary mineral found on the earth's surface.