Question
Question: Assuming the olivine series of minerals consists of crystal in which \[F{e^{2 + }}\] and \[M{g^{2 + ...
Assuming the olivine series of minerals consists of crystal in which Fe2+ and Mg2+ ions may substitute for each other causing substitutional impurity defect without changing the volume of the unit cell. In the olivine series of minerals, oxide ion exits as fcc with Si4+occupying 41th of octahedral void and divalent ion occupying 41th of the tetrahedral void. The density of Forsterite (Magnesium silicate) is 3.21ccg and that of Fayalite (Ferrous Silicate) is4.34ccg. If the density of olivine is3.88ccg, then which of the following statements is /are correct?
A. Olivine contains 40.71%Forsterite and 59.29%Fayalite.
B. Fayalite is Fe2SiO4and Forsterite isMgSiO4.
C. Percentage of ForsteriteMgSiO4is59.29.
D. Both options A and B.
Solution
Hint : Chemical composition of olivine falls somewhere close to pure Forsterite (MgSiO4) and pure Fayalite(Fe2SiO4). Around there Mgand can elective uninhibitedly for one another in the mineral’s nuclear design-in any proportion, known as “solid arrangement”.
Complete step-by-step solution:
According to the question we get-
Number of O−2atoms
Number of Si4+atoms =41×octahedral void
=41×4 =1Number of Mg2+ atoms 41×tetrahedral void
=41×8 =2We know the formula of Forsterite =MgSiO4 and Fayallite=Fe2SiO4
Let us assume the Forterite is x% and Fayalite is (100−x)%
Therefore,
And the percentage of Fayalite (100−40.71)=59.29.
Therefore, the right option is D.
Note: Olivine has additionally been utilized as a hard–headed material. It is utilized to make a headstrong block and utilized as projecting sand. It is the primary mineral found on the earth's surface.