Question
Question: Assuming that petrol is octane \(\left( {{C_8}{H_{18}}} \right)\)and has density \(0.8\)g/ml, \(1.42...
Assuming that petrol is octane (C8H18)and has density 0.8g/ml, 1.425litre of petrol on complete combustion will consume:
A.50 mole of O2
B.100 mole of O2
C.125 mole of O2
D.200 mole of O2
Solution
To solve this question, the knowledge of combustion and density are needed. Combustion means reaction of a substance with oxygen.
Formula used:
d = volumemass = vm.
n = mol.wt.mass
Complete step by step answer:
Molecular weight of octane (C8H18)=[12×8]+[18×1]=96+18=114 gmol−1
As density d = volumemass = vm
Therefore, volume of octane= 1.425 litre, density =0.8 g/mL,
It’s mass = 0.8×1.425×1000=1140g.
Now, no. of moles,
n = mol.wt.mass = 1141140 = 10moles of (C8H18)
The reaction between (C8H18)and O2for the combustion is:
2C8H18+25O2→16CO2+18H2O
So for 2 moles of octane, 25 moles of oxygen is required.
Therefore 10 mole of octane will consume, 225×10 = 125 moles of O2
So, the correct answer is option C.
Note:
1.This is the reaction that takes place in the internal combustion engine of any vehicle. The petrol is combusted in presence of oxygen and carbon dioxide and water vapour are released as products. This is an exothermic reaction and a high amount of heat energy is generated due to the combustion. This heat energy is converted into kinetic energy which runs the vehicle.
2.Burning of 1 L petrol releases about 2.3kg of carbon dioxide.
3.In this combustion reaction, hydrogen from the petrol combines with oxygen from air to form water vapour, while the carbon from the petrol combines with oxygen from air to form carbon dioxide.
4.The heat energy released during the reaction is from the dissociation of the bonds that store energy in the form of potential energy.