Question

Assuming that earth and mars move in circular orbits around the sun, with the martian orbit being 1.52 times the orbital radius of the earth. The length of the martian year in days is

• A. $( 1.52 ) ^ { 2 / 3 } \times 365$
• B. $( 1.52 ) ^ { 3 / 2 } \times 365$
• C. $( 1.52 ) ^ { 2 } \times 365$
• D. $( 1.52 ) ^ { 3 } \times 365$

Answer 1

Answer: (B)

$( 1.52 ) ^ { 3 / 2 } \times 365$

Answer 2

According to Kepler’s third law

Where is the mars-sun distances and is the earth-sun distance.

$\therefore \mathrm { T } _ { \mathrm { M } } = \left( \frac { \mathrm { R } _ { \mathrm { MS } } } { \mathrm { R } _ { \mathrm { ES } } } \right) ^ { 3 / 2 } \mathrm {~T} _ { \mathrm { E } }$

$\therefore$