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Question

Physics Question on Wave optics

Assuming human pupil to have a radius of 0.25cm0.25\, cm and a comfortable viewing distance of 25cm25\, cm, the minimum separation between two objects that human eye can resolve at 500nm500\, nm wavelength is

A

30μm30\, \mu m

B

1μm1\, \mu m

C

100μm100 \,\mu m

D

300μm300 \,\mu m

Answer

30μm30\, \mu m

Explanation

Solution

y=1.22λDd=500×109×25×1022×0.25×102y=1.22 \frac{\lambda D}{d}=\frac{500 \times 10^{-9} \times 25 \times 10^{-2}}{2 \times 0.25 \times 10^{-2}}
y=30μm\Rightarrow y=30 \,\mu m