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Question

Physics Question on Atoms

Assuming ff to be the frequency of first line in Balmer series, the frequency of the immediate next (i.e. second) line is Assuming ff to be the frequency of first line in Balmer series, the frequency of the immediate next (i.e. second) line is

A

0.50 f

B

1.35 f

C

2.05 f

D

2.70 f

Answer

1.35 f

Explanation

Solution

Balmer series is the series in which the spectral lines correspond to the transition of electron from some higher energy state to the lower energy state corresponding to nf=2n_{f}=2. Therefore, for Balmer series, nf=2n_{f}=2 and ni=3,4,5,n_{i}=3,4,5, \ldots
Frequency, of 1 st spectral line of Balmer
series f=RZ2c(122132)f=R Z^{2} c\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)
Or f=RZ2c×536....f=R Z^{2} c \times \frac{5}{36} ....(i)
Frequency of 2 nd spectral line of Balmer series
f=RZ2c(122142)f^{\prime}=R Z^{2} c\left(\frac{1}{2^{2}}-\frac{1}{4^{2}}\right)
or f=RZ2c×316....f^{\prime}=R Z^{2} c \times \frac{3}{16} ....(ii)
From Eqs. (i) and (ii), we have
ff=2027\frac{f}{f^{\prime}}=\frac{20}{27}
f=2720f=1.35f\therefore f^{\prime}=\frac{27}{20} f=1.35 f