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Question: Assuming coefficient of friction 0.25 between block and incline. Find the acceleration of each block...

Assuming coefficient of friction 0.25 between block and incline. Find the acceleration of each block in fig.

A

g/5

B

g/7

C

g/6

D

None of these

Answer

g/5

Explanation

Solution

m2a = T1 – T2 – m2g sin 37 - μm2g cos 37

or a = T1T2 m2\frac { \mathrm { T } _ { 1 } - \mathrm { T } _ { 2 } } { \mathrm {~m} _ { 2 } } - g sin 37 - 14\frac { 1 } { 4 } g cos 37

or T1 – T2 – 0.8g = a …….. (ii)

T2 – 0.5 g = 0.5a ……… (iii)

m1 g – T1 = m1a

or 2g – T1 = 2a …. …. (i)

Adding (i), (ii) and (iii) 3.5 a = 0.7 g

or a = g/5.