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Question

Physics Question on Gravitation

Assume that the earth moves around the sun in a circular orbit of radius R and there exists a planet which also moves around the sun in circular orbit with an angular speed twice as large as that of the earth. The radius of the orbit of the planet is

A

223R2-\frac{2}{3}R

B

223R2\frac{2}{3}R

C

213R2\frac{-1}{3}R

D

R2\frac{R}{\sqrt{2}}

Answer

223R2-\frac{2}{3}R

Explanation

Solution

T2r3,rErP=(TETP)23=(ωPωE)23T^{2} \propto r^{3},\frac{rE}{rP}=\left(\frac{T_{E}}{T_{P}}\right)^{\frac{2}{3}} =\left(\frac{\omega_{P}}{\omega_{E}}\right)^{\frac{2}{3}} Rrp=(2)23,rp=223R\frac{R}{r_{p}} = \left(2\right)^{\frac{2}{3}} , r_{p} =2^{-\frac{2}{3}R}