Question
Question: **Assertion:** \(S{{F}_{6}}\) exists but \(S{{H}_{6}}\) does not. **Reason:** \(d\pi -p\pi \) bond...
Assertion: SF6 exists but SH6 does not.
Reason: dπ−pπ bonding cannot take place in SH6.
A.Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
B.Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
C.Assertion is correct but Reason is incorrect
D.Assertion is incorrect but Reason is correct.
Solution
To solve this question first we have to predict the geometry of the compound. SF6 has six electrons in the bond pair and no electrons or lone pair on the central atom which is the sulphur atom. The shape of SF6 molecule is octahedral.
Complete answer:
Assertion: SF6 exists but SH6 does not.
We know that fluorine is the strongest oxidising agent and hydrogen is the weakest oxidising agent. In SF6 fluorine oxidises sulphur to its maximum oxidation state which is +6 and this leads to the formation of SF6. This molecule is octahedral in shape.
Hydrogen is a very weak oxidizing agent as compared to fluorine this means that hydrogen is not able to oxidise sulphur to its maximum oxidation state. Hence, SH6 does not exist. And also, we can say that sulphur is more electropositive than fluorine but sulphur is less electropositive than hydrogen. Hence the only compound possible with hydrogen is H2S and SH6.
Reason: dπ−pπ bonding cannot take place in SH6.
Hydrogen is a very weak oxidising agent and the stable octahedral configuration is only for SX6 molecules containing electronegative ligand atoms like fluorine.
Hence the correct answer is option (B) i.e. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.
Note:
To solve this type of question, we should first check both the assertion and reason separately because it might be possible that the reason is correct but the assertion is incorrect. only after this we will find the relation between them.