Question
Question: Assertion: \(S{{b}_{2}}{{S}_{3}}\) is not soluble in yellow ammonium sulfide. Reason: The common i...
Assertion: Sb2S3 is not soluble in yellow ammonium sulfide.
Reason: The common ion effect due to S2− ions reduce solubility of Sb2S3.
(a)- Both the assertion and the reason are correct and the reason is the correct explanation for the assertion.
(b)- Both the assertion and the reason are correct and the reason is not the correct explanation for the assertion.
(c)- The assertion is correct but the reason is incorrect.
(d)- Both the assertion and the reason are incorrect.
Solution
When the color of the ammonium sulfide changes from white to yellow the solubility will increase as the sulfur ion increases which will increase the common ion effect.
Complete step by step answer:
The given assertion says that the Sb2S3 is not soluble in yellow ammonium sulfide but this is not true because when the color of the ammonium sulfide changes from white to yellow the solubility of Sb2S3 increases. When the reaction between the Sb2S3 and yellow ammonium sulfide will form thiosalts. The reaction is given below:
Sb2S3+3(NH4)2S→2(NH4)3SbS2
- This is due to the fact that when the color changes from white to yellow the number of sulfur increases, therefore the ions of the sulfur atoms increases, i.e., S2− ions. So, as the amount of the sulfur ions increases the common ion effect also increases. Therefore, we can say that as the common ion effect increases the solubility will also increase. Hence the reason is also incorrect.
So, the correct answer is “Option D”.
Note: Generally the solubility of the solute will decrease due to the common ion effect but the common ion effect due to S2− ions increase the solubility of Sb2S3 is an exception. Also as the atomic number increases the solubility increases.