Solveeit Logo

Question

Question: Assertion : If the current of a lamp decreases by 20%, the percentage decrease in the illumination o...

Assertion : If the current of a lamp decreases by 20%, the percentage decrease in the illumination of the lamp is 40%.
Reason: Illumination of the lamp is directly proportional to square of the current through a lamp.

A) Both (A) and (R) are true and (R) is the correct explanation of A.
B) Both (A) and (R) are true but (R) is not the correct explanation of A.
C) (A) is true but (R) is false
D) (A) is false but (R) is true

Explanation

Solution

Yes, the illumination of lamp is directly proportional to square of the current
through the lamp and the formula E=I2RTE = {I^{^2}}RT can be used to find the solution.

Complete step by step answer: The illumination from a lamp is measured as a form of energy coming from the lamp.
Using the formula for energy E=I2RTE = {I^{^2}}RT, where I is the current flowing, R is the resistance, T is the time for which current flows.

We can find out the amount of illumination.
Let the initial and final current flowing be I1I_1 and I2I_2 respectively.
Initial Energy, E1=I12RT{E_1} = I_1^2RT
Final Current,
I2=I120%I1 I2=80%I1=0.8I1  {I_2} = {I_1} - 20\% {I_1} \\\ \Rightarrow {I_2} = 80\% {I_1} = 0.8{I_1} \\\
So, final energy, E2E_2
E2=I22RT=(0.8I1)2RT E2=0.64I12RT E2=0.64E1  {E_2} = I_2^2RT = {\left( {0.8{I_1}} \right)^2}RT \\\ \Rightarrow {E_2} = 0.64I_1^2RT \\\ \Rightarrow {E_2} = 0.64{E_1} \\\
So, the percentage decrease in illumination is given by E1E2E1×100=E10.64E1E1×100=36%\dfrac{{{E_1} - {E_2}}}{{{E_1}}} \times 100 = \dfrac{{{E_1} - 0.64{E_1}}}{{{E_1}}} \times 100 = 36\%
Therefore, the correct option is D), as the reason is correct but the assertion is false.

Note: Because illumination is directly proportional to the square of the current and not to twice the current, we can directly say that the assertion is false.