Solveeit Logo

Question

Mathematics Question on Arithmetic Progression

Assertion (A): The sum of the first fifteen terms of the AP 21,18,15,12,21, 18, 15, 12, \dots is zero.
Reason (R): The sum of the first nn terms of an AP with first term aa and common difference dd is given by: Sn=n2[a+(n1)d].S_n = \frac{n}{2} \left[ a + (n - 1) d \right].

A

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

B

Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A)

C

Assertion (A) is true, but Reason (R) is false.

D

Assertion (A) is false, but Reason (R) is true.

Answer

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation

Solution

For the AP: a=21a = 21, d=1821=3d = 18 - 21 = -3. Sum of 15 terms:
Sn=n2[2a+(n1)d]S_n = \frac{n}{2} \left[ 2a + (n - 1)d \right]
Substitute n=15n = 15, a=21a = 21, d=3d = -3:
S15=152[2(21)+(151)(3)]=152[4242]=0S_{15} = \frac{15}{2} \left[ 2(21) + (15 - 1)(-3) \right] = \frac{15}{2} \left[ 42 - 42 \right] = 0
Both (A) and (R) are true, and (R) explains (A).