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Question: Assertion(A): In the expansion \[{(x + {x^{ - 2}})^n}\] the coefficient of eighth term and nineteent...

Assertion(A): In the expansion (x+x−2)n{(x + {x^{ - 2}})^n} the coefficient of eighth term and nineteenth term are equal, then n=25.
Reason (R): Middle term in the expansion of (x+a)n{(x + a)^n} has the greatest binomial coefficient.

  1. Both A and R are individually true and R is the correct explanation of A.
  2. Both A and R are individually true but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Explanation

Solution

It’s very easy to calculate (a+b)2  or  (a+b)3{(a + b)^2}\;or\;{(a + b)^3} but how can we calculate if the power is large?
For this purpose, we use Binomial Theorem,
Binomial theorem is a way of expanding any expression which is raised to a large power.
Now as per binomial theorem,
(x + y)n  =  nΣr=0  nCr  xn − r  ⋅ yr  {\left( {x{\text{ }} + {\text{ }}y} \right)^n}\; = {\;^n}{\Sigma _{r = 0}}\;n{C_r}\;{x^{n{\text{ }}-{\text{ }}r\;}}\cdot{\text{ }}{y^r}\;
Where n can be any natural number and x and y can be real numbers.
Here the term apart from the variable is known as the coefficient.
General term in the above expression is given by,
Tr+1  = nCr  xn−r  . yr{T_{r + 1}}\; = {\text{ }}n{C_r}\;{x^{n - r}}\;.{\text{ }}{y^r}
Also, nCr  =n!r!(n−r)!n{C_r}\; = \dfrac{{n!}}{{r!(n - r)!}}.
And nCr  =nCn−rn{C_r}\; = n{C_{n - r}}.

Complete Answer:
Assertion:
Now it is given that the coefficient of eighth and the nineteenth term are equal, hence
Coefficient of T7+1  and T18+1{T_{7 + 1}}\;and{\text{ }}{T_{18 + 1}} are equal.

And as we know that Tr+1  = nCr  xn−r  . yr{T_{r + 1}}\; = {\text{ }}n{C_r}\;{x^{n - r}}\;.{\text{ }}{y^r}
T7+1  = nC7  xn−7  . y7{T_{7 + 1}}\; = {\text{ }}n{C_7}\;{x^{n - 7}}\;.{\text{ }}{y^7}
And, T18+1= nC18  xn−18  . y18{T_{18 + 1}} = {\text{ }}n{C_{18}}\;{x^{n - 18}}\;.{\text{ }}{y^{18}}
Hence, the coefficient of T7+1  ={T_{7 + 1}}\; = the coefficient of T18+1  {T_{18 + 1}}\;
i.e. nC7= nC18n{C_7} = {\text{ }}n{C_{18}}
As we know that nCr  =nCn−rn{C_r}\; = n{C_{n - r}}
Hence, nC18  =nCn−7n{C_{18}}\; = n{C_{n - 7}}
Equating the above equation, we get,

{n - 7{\text{ }} = {\text{ }}18} \\\ {n{\text{ }} = {\text{ }}25} \end{array}$$ Hence the assertion(A) is correct, i.e. in the expansion $${(x + {x^{ - 2}})^n}$$ the coefficient of eighth term and nineteenth term are equal, then n=25. **Reason:** Now We can see that, the coefficient of ‘x’ and ‘a’ are, ![](https://www.vedantu.com/question-sets/e5891fdd-0851-45d8-96ee-c706cb0fcf1b5184917655200801475.png) And if we will continue the expansion for larger power and follow the trend, the coefficient will be as follows, ![](https://www.vedantu.com/question-sets/9dac8b89-8531-46a2-9a0d-d46c1ec8666c1992296661758762800.png) This sequence is known as the Pascal’s triangle and each number is found by adding the two numbers directly above it. Here in the end 20 comes by adding two 10’s above it. Hence clearly we can see that the value of the middle term is largest. Thus the Reason (R) is individually correct i.e. the middle term in the expansion of $${(x + a)^n}$$ has the greatest binomial coefficient. But (R) is not the correct explanation of the Assertion (A). **So, option (B) is the correct answer.** **Note:** The number of terms in $$\left( {n{\text{ }} + {\text{ }}r{\text{ }} - {\text{ }}1} \right){C_{r{\text{ }}-{\text{ }}1}}$$is n+1. And the number of terms in the expansion of $${({x_{1\;}} + {\text{ }}{x_{2\;}} + {\text{ }} \ldots {\text{ }}{x_r})^n}\;\;$$is $$\left( {n{\text{ }} + {\text{ }}r{\text{ }} - {\text{ }}1} \right){C_{r{\text{ }}-{\text{ }}1}}$$.