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Question

Physics Question on mechanical properties of solids

As shown in the figure, forces of 105N10^5\, N each are applied in opposite directions, on the upper and lower faces of a cube of side 10cm10\, cm, shifting the upper face parallel to itself by 0.5cm0.5 \,cm. If the side of another cube of the same material is 20cm20\, cm, then under similar conditions as above, the displacement will be :

A

0.25 cm

B

0.37 cm

C

0.75 cm

D

1.00 cm

Answer

0.25 cm

Explanation

Solution

Given: Force applied F=103N;F=10^{3} \,N ;
side of cube x=10m=10×102m;x=10 m =10 \times 10^{-2} \,m ;
shift dx=0.5cm=0.5×102md x=0.5 cm =0.5 \times 10^{-2}\, m