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Physics Question on Ray optics and optical instruments

As shown in the figure, after passing through the medium 1. The speed of light v2 in medium 2 will be: (Given c=3×108ms−1c = 3 \times 10^8 ms^{-1})
speed of light v2 in medium 2

A

1.0×108 ms−11.0 \times 10^8 \,ms ^{-1}

B

0.5×108 ms−10.5 \times 10^8 \, ms ^{-1}

C

1.5×108 ms−11.5 \times 10^8 \,ms ^{-1}

D

3.0×108 ms−13.0 \times 10^8 \, ms ^{-1}

Answer

1.0×108 ms−11.0 \times 10^8 \,ms ^{-1}

Explanation

Solution

From the given options the correct answer is option (A): 1.0×108 ms−11.0 \times 10^8 \,ms ^{-1}