Question

As shown in the figure a block of mass $10\, kg$ lying on a horizontal surface is pulled by a force $F$ acting at an angle $30^{\circ}$, with horizontal For $\mu_{ s }=0.25$, the block will just start to move for the value of $F$ : [Given g=10ms-2] is

• A. $20\, N$
• B. $35.7\, N$
• C. $33.3 \,N$
• D. $25.2\, N$

Answer 1

Answer: (D)

$25.2\, N$

Answer 2

N=Mg−FSin30∘
=mg−2F​=100−2F​=2200−F​
FCos30∘=μN
3​2F​=0.25×(2200−F​)
43​F=200−F
F=43​+1200​=25.22