Question

As show in the figure, in the steady state, the charge stored in the capacitor is _________ × 10–6 C.

Fig.

Answer 1

The correct answer is 10
At steady state potential difference across capacitor
$V_c =\frac{10×100}{110} V$
Q = CVc
$= \frac{1.1×10^{-6}×10×100}{110}C$
$= 10\ µC$