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Question

Physics Question on electrostatic potential and capacitance

As per this diagram a point charge +q+q is placed at the origin OO. Work done in taking another point charge Q-Q from the point AA [coordinates (0,a)](0, a)]

A

zero

B

(qQ4πε01a2)2a\left(\frac{-q Q}{4 \pi \varepsilon_{0}} \frac{1}{a^{2}}\right) \sqrt{2} a

C

(qQ4πε01a2)\left(\frac{q Q}{4 \pi \varepsilon_{0}} \frac{1}{a^{2}}\right)

D

(qQ4πε01a2)2a\left(\frac{q Q}{4 \pi \varepsilon_{0}} \frac{1}{a^{2}}\right) \sqrt{2} a

Answer

zero

Explanation

Solution

The work done in carrying a test charge consists in product of difference of potentials at points AA and BB and value of test charge.