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Question: : As per this diagram a point charge \( + q\) is placed at the origin O. Work done in taking another...

: As per this diagram a point charge +q + q is placed at the origin O. Work done in taking another point charge Q - Q from the point A [coordinates (0,a)(0,a)] to another point B [coordinates (a,0)(a,0)] along the straight path AB is,

A.A. Zero
B.  (qQ4π012)2a C.   (qQ4π012)a2 D.   (qQ4π012)2a  B.\;\left( {\dfrac{{ - qQ}}{{4\pi { \in _0}}}\dfrac{1}{2}} \right)\sqrt 2 a \\\ C.\;{\text{ }}\left( {\dfrac{{qQ}}{{4\pi { \in _0}}}\dfrac{1}{2}} \right) \cdot \dfrac{a}{{\sqrt 2 }} \\\ D.\;{\text{ }}\left( {\dfrac{{qQ}}{{4\pi { \in _0}}}\dfrac{1}{2}} \right) \cdot \sqrt 2 a \\\

Explanation

Solution

The electric potential energy is the energy which results from the conservative coulomb forces and which is associated with the configuration of the particular set of point charges within the defined system. It is also known as the electrostatic potential energy and is measured in joules.

Complete step by step answer:
In an electric field, let us consider that there are two charges q1 and q2{q_1}{\text{ and }}{{\text{q}}_2} which are placed at the distance r1 and r2{r_{1{\text{ }}}}and{\text{ }}{{\text{r}}_2} respectively.
Then the potential energy of two charge system is U=q1q24π0r12U = \dfrac{{{q_1}{q_2}}}{{4\pi { \in _0}{r_{12}}}}
Where r12{r_{12}} is the distance between the two electric charges.
When the charge Q - Q at the point A, the potential energy UA=(Q)q4π0(OA){U_A} = \dfrac{{( - Q)q}}{{4\pi { \in _0}(OA)}}
UA=(Q)q4π0(a)..... (1){U_A} = \dfrac{{( - Q)q}}{{4\pi { \in _0}(a)}}{\text{}}.....{\text{ (1)}}
When the charge Q - Q at the point B, the potential energy UB=(Q)q4π0(OB){U_B} = \dfrac{{( - Q)q}}{{4\pi { \in _0}(OB)}}
UB=(Q)q4π0(a)..... (2){U_B} = \dfrac{{( - Q)q}}{{4\pi { \in _0}(a)}}{\text{}}.....{\text{ (2)}}
Work done, WAB=UBUA{W_{AB}} = {U_B} - {U_A}
Place the values in the above equations by using the equations (1) and (2)(1){\text{ and (2)}}
WAB=(Q)q4π0(a)(Q)q4π0(a){W_{AB}} = \dfrac{{( - Q)q}}{{4\pi { \in _0}(a)}} - \dfrac{{( - Q)q}}{{4\pi { \in _0}(a)}}
Minus between two the same terms gives the resultant value zero.
WAB=0\therefore{W_{AB}} = 0
Therefore, work done is zero.

Hence, from the given multiple choices – the option A is the correct answer.

Note: In physics, the charge is the physical property of the matter which causes force when placed in an electro-magnetic field. Charge is also known as the electric charge, the electrical charge or the electrostatic charge and is symbolized as “q” and is measured in coulomb.Remember the basic concepts and formulas to solve these types of questions.