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Question

Physics Question on Centre of mass

As per the given figure, a small ball PP slides down the quadrant of a circle and hits the other ball QQ of equal mass which is initially at rest Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball QQ after collision will be :(g=10m/s2)\left( g =10 \,m / s ^2\right)a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest

A

4m/s4\, m / s

B

0

C

0.25m/s0.25 \,m / s

D

2m/s2\, m / s

Answer

2m/s2\, m / s

Explanation

Solution

The velocities will be interchanged after collision.
Speed of P just before collision =2gh​
=2×10×0.2​=2m/s