<>As per given figure, a weightless pulley (P) is attached o... | Physics | SolveeIt | Solveeit

Today, October 3

Question

<>As per given figure, a weightless pulley $P$ is attached on a double inclined frictionless surfaces. The tension in the string (massless) will be (if $g =10 \,/ s ^2$ )

A

$(4 \sqrt{3}-1) N$

B

$4(\sqrt{3}-1) N$

C

$(4 \sqrt{3}+1) N$

D

$4(\sqrt{3}+1) N$

Answer

$(4 \sqrt{3}+1) N$

Explanation

Solution

As per given figure, a weightless pulley P is attached on a double inclined frictionless surfaces. The tension in the string massless will be if g =10 / s 2

Solving (1) and (2) we get.
$20\sqrt3−T=4T−20$

$T=4(\sqrt3+1)N$