Question

As a result of sp hybridization, we get;
(A) Two mutually perpendicular orbitals.
(B) Two orbitals at $180{}^\circ .$
(C) Four orbitals in tetrahedral direction.
(D) Three orbitals in the same plane.

Answer 1

We know that the number of hybrid orbitals formed is equal to the number of atomic orbitals participating in hybridization. Three p-orbitals differ from each other in the way the lobes are oriented whereas they are identical in terms of size, shape, and energy.

Complete answer:
The regions of space in which electrons are most likely to be found are known as an orbital. -Each orbital is designated by a number and a letter. The number denotes the energy level of the electron in the orbital whereas the letter refers to the shape of the orbital. There are four different shapes of the orbital that is s-orbital, p-orbital, d-orbital, and f-orbital.
The s, p, d, and f respectively stand for the words sharp, primary, diffuse, and fundamental. A spherically symmetric orbital, like a hollow ball made of rather fluffy arterial with a nucleus at the center is known as an s-orbital. S-orbital has only one atomic orbital in it. s-orbital is symmetric in having the probability of finding the electron at a given distance equal in all the directions
In sp hybridization , we find two orbitals at $180{}^\circ$ degrees. The number of hybrid orbitals formed is equal to the number of atomic orbitals participating, which is in its current state. The angle between these two is equal to $360{}^\circ$ degrees divided by the number of orbitals. $180{}^\circ$
Therefore, the correct answer is option B.

Note:
Remember that d-orbital is a dumbbell-shaped orbital. There are five d orbitals, namely . Four of the five d-orbitals are cloverleaf shaped and the fifth orbital is like an elongated dumbbell with a doughnut in its middle. f-orbitals are at the fourth and higher levels and have seven orbitals which can accommodate a maximum of $14$ electrons in it.