Question

Arrange thefollowingin increasing order of oxidation state of Ni.

$K_{2}\lbrack Ni(CN)_{4}\rbrack,K_{2}\lbrack NiF_{6}\rbrack,Ni(CO)_{4}$

• A. $Ni(CO)_{4},K_{2}\lbrack Ni(CN)_{4}\rbrack,K_{2}\lbrack NiF_{6}\rbrack$
• B. $K_{2}\lbrack Ni(CN)_{4}\rbrack,Ni(CO)_{4},K_{2}\lbrack NiF_{6}\rbrack$
• C. $Ni(CO)_{4},K_{2}\lbrack NiF_{6}\rbrack,K_{2}\lbrack Ni(CN)_{4}\rbrack$
• D. $K_{2}\lbrack NiF_{6}\rbrack,K_{2}\lbrack Ni(CN)_{4}\rbrack,Ni(CO)_{4}$

Answer 1

Answer: (A)

$Ni(CO)_{4},K_{2}\lbrack Ni(CN)_{4}\rbrack,K_{2}\lbrack NiF_{6}\rbrack$

Answer 2

: $K_{2}\lbrack Ni(CN)_{4}\rbrack: + 2 + x + 4( - 1) = 0 \Rightarrow x = + 2$

$K_{2}\lbrack NiF_{6}\rbrack: + 2 + x + 6( - 1) = 0 \Rightarrow x = + 4$

$Ni(CO)_{4}:x + 0 = 0 \Rightarrow x = 0$