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Question: Arrange the oxides of nitrogen in increasing order of oxidation state of N from + 1 to + 5....

Arrange the oxides of nitrogen in increasing order of oxidation state of N from + 1 to + 5.

A

N2O<N2O3<NO2<N2O5<NON_{2}O < N_{2}O_{3} < NO_{2} < N_{2}O_{5} < NO

B

N2O<NO<N2O3<NO2<N2O5N_{2}O < NO < N_{2}O_{3} < NO_{2} < N_{2}O_{5}

C

N2O5<NO2<N2O3<NO<N2ON_{2}O_{5} < NO_{2} < N_{2}O_{3} < NO < N_{2}O

D

NO<N2O<NO2<N2O3<N2OsNO < N_{2}O < NO_{2} < N_{2}O_{3} < N_{2}O_{s}

Answer

N2O<NO<N2O3<NO2<N2O5N_{2}O < NO < N_{2}O_{3} < NO_{2} < N_{2}O_{5}

Explanation

Solution

: Oxides: N2O→+1,NO→+2N_{2}O \rightarrow + 1,NO \rightarrow + 2

N2O3→+3,NO2→+4,N2O5→+5N_{2}O_{3} \rightarrow + 3,NO_{2} \rightarrow + 4,N_{2}O_{5} \rightarrow + 5