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Question: Arrange the holgens \(F_{2},Cl_{2}Br_{2}I_{2}\)in order of their increasing reactivity with alkanes...

Arrange the holgens F2,Cl2Br2I2F_{2},Cl_{2}Br_{2}I_{2}in order of their

increasing reactivity with alkanes.

A

I2<Br2<Cl2<F2I_{2} < Br_{2} < Cl_{2} < F_{2}

B

Br2<Cl2<F2<l2Br_{2} < Cl_{2} < F_{2} < l_{2}

C

F2<Cl2<Br2<I2F_{2} < Cl_{2} < Br_{2} < I_{2}

D

Br2<I2<Cl2F2Br_{2} < I_{2} < Cl_{2}F_{2}

Answer

I2<Br2<Cl2<F2I_{2} < Br_{2} < Cl_{2} < F_{2}

Explanation

Solution

Rate of reaction of alkanes with halogens is lF2>Cl2>Br2>I2F_{2} > Cl_{2} > Br_{2} > I_{2}Reactivity decrease down the group as the electronegativity of the halogen decreases down the group.