Question
Question: Arrange the following lengths in descending order of their magnitudes: Light year, parsec, and Astro...
Arrange the following lengths in descending order of their magnitudes: Light year, parsec, and Astronomical unit.
Solution
We know the distance traveled by light in one year is called light-year(ly). It is used to measure large distances. A parsec is a distance at which one astronomical unit subtends an angle of one second of arc, and the Astronomical unit measures the distance between the earth and the sun. A light-year is also related to astronomy and parsec. For the arrangement of these lengths in descending order, we calculate the values of each.
Complete step by step answer:
We know that one light-year is equal to the distance that light travels in a year.
∴1ly=c×1yr
Here c is the speed of light in a vacuum, which is equal to 3×108sm and 1 ly means one light year. Hence on simplifying the above relation, we get,
⇒1ly=3×108m/s×365×24×60×60s.
⇒1ly=9.46×1015m
The relation between light-year (ly) and astronomical unit (A.U)
1(ly)=9.46×1015m …… (I) and,
1A.U=1.5×1011m …… (II)
Here 1 A.U. means 1 astronomical unit.
On dividing equations(I) and (II), we get:
1A.U1ly=1.5×1011m9.456×1015m
⇒1A.U1ly=6.3×104
∴1ly=6.3×104A.U
The relation between the light-year (ly) and parsec
Again 1ly=9.46×1015m …… (III)
And 1parsec=3.1×1016m…… (IV)
On dividing equations (III) and (IV), we get
1ly1parsec=9.46×1015m3.1×1016m
1ly1parsec=3.28
∴1parsec=3.28ly
Suppose we saw the actual value of light year, parsec, A.U. (Astronomical unit). In that case, we will observe that parsec has greater value than a light-year, and a light year is greater than the Astronomical unit.
Therefore arrange in descending order of their magnitudes parsec>light year>astronomical unit.
⇒1016>1015>1011
Note: The lengths of a light-year, parsec, and astronomical unit are the same and scientifically proven throughout the universe. When we calculate the large distances and very small distances, we use non-S.I units of lengths for such measurements.