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Chemistry Question on Chemical bonding and molecular structure

Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in SiO44−,ClO4−,PO43−,SO42−SiO_4^{4-},ClO_4^- ,PO_4^{3-},SO_4^{2-}

A

ClO4−>SO42−>PO43−>SiO44−ClO_4^- > SO_4^{2-} > PO_4^{3-} > SiO_4^{4-}

B

SiO44−>PO43−>SO42−>ClO4−SiO_4^{4-} > PO_4^{3-} > SO_4^{2-} > ClO_4^{-}

C

SiO44−>PO43−>ClO4−>SO42−SiO_4^{4-} > PO_4^{3-} > ClO_4^{-} > SO_4^{2-}

D

SiO44−>SO42−>PO43−>ClO4−SiO_4^{4-} > SO_4^{2-} > PO_4^{3-} > ClO_4^-

Answer

SiO44−>PO43−>SO42−>ClO4−SiO_4^{4-} > PO_4^{3-} > SO_4^{2-} > ClO_4^{-}

Explanation

Solution

As the number of double bonds increases, X-O bond length decreases