Question

Arrange the following in the order of their increasing masses. \({(Atomic\, mass : O = 16, N = 14)}) I. One atom of oxygen II. One atom of nitrogen III. \(1 \times 10^{-10}) mole of oxygen

• A. II < I < III
• B. I < II < III
• C. III < II < I
• D. II < III < I

Answer 1

Answer: (A)

II < I < III

Answer 2

I. Mass of one atom of oxygen
$= \frac{16}{6.023\times10^{23}} = 2.66 \times10^{-23} g$
II. Mass of one atom of nitrogen
$= \frac{14}{6.023\times10^{23}} = 2.32 \times10^{-23} g$
III. Mass of $1 \times 10^{-10}$ mole of oxygen
$= 16 \times 10^{-10} g$
So, the order of increasing masses is $II < I < III$.