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Chemistry Question on Some basic concepts of chemistry

Arrange the following in the order of increasing mass (atomic mass O=16,Cu=63,O=16,Cu=63, N=14N=14 ) I. One atom of oxygen II. One atom of nitrogen III. 1×10−101 \times 10^{-10} mole of oxygen IV. 1×10−101 \times 10^{-10} mole of copper

A

II<I<III<IVII < I < III < IV

B

I<II<III<IVI < II < III < IV

C

III<II<IV<IIII < II < IV < I

D

IV<II<III<IIV < II < III < I

Answer

II<I<III<IVII < I < III < IV

Explanation

Solution

I. One atom of oxygen =16×1.66×10−24g=16\times 1.66\times {{10}^{-24}}g
II. One atom of nitrogen =14×1.66×10−24g=14\times 1.66\times {{10}^{-24}}g
III. 1×10−101\times {{10}^{-10}} mole of oxygen =32×1×10−10g=32\times 1\times {{10}^{-10}}g
IV. 1×10−101\times {{10}^{-10}} mole of copper
=63×1×10−10g=63\times 1\times {{10}^{-10}}g
Thus, the correct order of increasing mass
II<I<III<IVII < I < III < IV