Solveeit Logo
Login

Question

Question: Arrange the following in order of increasing dipole moment : \(H_{2}O,H_{2}S,BF_{3}\)...

Arrange the following in order of increasing dipole moment : H2O,H2S,BF3H_{2}O,H_{2}S,BF_{3}

A

BF3<H2S<H2OBF_{3} < H_{2}S < H_{2}O

B

H2S<BF3<H2OH_{2}S < BF_{3} < H_{2}O

C

H2O<H2S<BF3H_{2}O < H_{2}S < BF_{3}

D

BF3<H2O<H2SBF_{3} < H_{2}O < H_{2}S

Answer

BF3<H2S<H2OBF_{3} < H_{2}S < H_{2}O

Explanation

Solution

: In BF3BF_{3}dipole moment is zero due to its symmetrical structure. Summations of all dipoles is zero.

In H2SH_{2}Sand H2OH_{2}Odue to unsymmetrical structure net +ve dipole is there. H2OH_{2}Ohas higher dipole due to higher electronegativity of oxygen than sulphur.