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Question: Arrange the following in increasing value of magnetic moments (i) \(\lbrack Fe(CN)_{6}\rbrack^{4 -}...

Arrange the following in increasing value of magnetic moments

(i) [Fe(CN)6]4\lbrack Fe(CN)_{6}\rbrack^{4 -} (ii) [Fe(CN)6]3\lbrack Fe(CN)_{6}\rbrack^{3 -}

(iii) [Cr(NH3)6]3+\lbrack Cr(NH_{3})_{6}\rbrack^{3 +} (iv) [Ni(H2O)4]2+\lbrack Ni(H_{2}O)_{4}\rbrack^{2 +}

A

(i) < (ii) < (iii) < (iv)

B

(i) < (ii) < (iv) < (iii)

C

(ii) < (iii) < (i) < (iv)

D

(iii) < (i) < (ii) < (iv)

Answer

(i) < (ii) < (iv) < (iii)

Explanation

Solution

[Fe(CN)6]4\lbrack Fe(CN)_{6}\rbrack^{4 -} No. of unpaired electrons = 0

[Fe(CN)6]3\lbrack Fe(CN)_{6}\rbrack^{3 -} No. of unpaired electrons = 1

[Ni(H2O)4]2+\lbrack Ni(H_{2}O)_{4}\rbrack^{2 +} No. of unpaired electrons = 2

[Cr(NH3)6]3+\lbrack Cr(NH_{3})_{6}\rbrack^{3 +} No. of unpaired electrons = 3