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Question

Chemistry Question on subshell electronic configuration

Arrange the following elements in the increasing order of number of unpaired electrons in it.
(A) Sc
(B) Cr
(C) V
(D) Ti
(E) Mn
Choose the correct answer from the options given below:

A

(C) << (E) << (B) << (A) << (D)

B

(B) << (C) << (D) << (E) << (A)

C

(A) << (D) << (C) << (B) << (E)

D

(A) << (D) << (C) << (E) << (B)

Answer

(A) << (D) << (C) << (E) << (B)

Explanation

Solution

The electronic configurations and the number of unpaired electrons for each element are as follows:

Sc: [Ar]4s23d1(1 unpaired electron)[ \text{Ar} ] 4s^2 3d^1 \quad (1 \text{ unpaired electron})
Cr: [Ar]4s13d5(6 unpaired electrons)[ \text{Ar} ] 4s^1 3d^5 \quad (6 \text{ unpaired electrons})
V: [Ar]4s23d3(3 unpaired electrons)[ \text{Ar} ] 4s^2 3d^3 \quad (3 \text{ unpaired electrons})
Ti: [Ar]4s23d2(2 unpaired electrons)[ \text{Ar} ] 4s^2 3d^2 \quad (2 \text{ unpaired electrons})
Mn: [Ar]4s23d5(5 unpaired electrons)[ \text{Ar} ] 4s^2 3d^5 \quad (5 \text{ unpaired electrons})

Arranging them in increasing order of unpaired electrons, we get:

Sc (A)<Ti (D)<V (C)<Mn (E)<Cr (B)\text{Sc (A)} < \text{Ti (D)} < \text{V (C)} < \text{Mn (E)} < \text{Cr (B)}