Question

Arrange the following complexes in increasing order of conductivity of solutions.

(i) $\lbrack Co(NH_{3})_{3}Cl_{3}\rbrack$

(ii) $\lbrack Co(NH_{3})_{4}Cl_{2}\rbrack Cl$

(iii) $\lbrack Co(NH_{3})_{6}\rbrack Cl_{3}$

(iv) $\lbrack Co(NH_{3})_{5}Cl\rbrack Cl_{2}$

• A. (i) < (ii) < (iv) < (iii)
• B. (ii) < (i) < (iii) < (iv)
• C. (i) < (iii) < (ii) < (iv)
• D. (iv) < (i) < (ii) < (iii)

Answer 1

Answer: (A)

(i) < (ii) < (iv) < (iii)

Answer 2

Higher the number of ions in the solutions, higher is the conductivity.

No. of ion : $\lbrack Co(NH_{3})_{3}Cl_{3}\rbrack = 0;$

$\lbrack Co(NH_{3})_{4}Cl_{2}\rbrack Cl = 2$

$\lbrack Co(NH_{3})_{5}Cl\rbrack Cl_{2} = 3;\lbrack Co(NH_{3})_{6}\rbrack Cl_{3} = 4$