Question

Arrange the following carbanions in order of their decreasing stability. $\left(I\right) H_{3}C - C \equiv C^{-}$ $\left(II\right) H - C \equiv C^{-}$ $\left(III\right) H_{3}C - CH^{-}_{2}$

• A. $I > II > III$
• B. $II > I > HI$
• C. $III > II > I$
• D. $III > I > II$

Answer 1

Answer: (B)

$II > I > HI$

Answer 2

The order of decreasing stability of carbanions is: $sp$-hybridised carbon atom is more electronegative than $sp^3$-hybridised carbon atom and hence, can accommodate the negative charge more effectively. $?