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Question: Arrange the following aqueous solution in the order of their increasing boiling points (i) \(10^{- ...

Arrange the following aqueous solution in the order of their increasing boiling points

(i) 10−4MNaCl10^{- 4}MNaCl (ii) 10−4MUrea10^{- 4}MUrea

(iii) 10−3MMgCl210^{- 3}MMgCl_{2} (iv) 10−2MNaCl10^{- 2}MNaCl

A

(i) < (ii) < (iv) < (iii)

B

(ii) < (ii) = (iii) < (iv)

C

(ii) < (i) < (iii) < (iv)

D

(iv) < (iii) < (i) = (ii)

Answer

(ii) < (i) < (iii) < (iv)

Explanation

Solution

For 10−4MNaCli=210^{- 4}MNaCl i = 2

10−4MUrea10^{- 4}MUrea i = 1

10−3MMgCl210^{- 3}MMgCl_{2} i = 3

10−2MNacl10^{- 2}MNacl i = 2

More the value of I, more will be the elevation in boiling point hence increasing order of boiling points is

10−4MUrea<10−4MNaCl<10−3MMgCl2<10−2MNaCl10^{- 4}MUrea < 10^{- 4}MNaCl < 10^{- 3}MMgCl_{2} < 10^{- 2}MNaCl