Question

Arrange the bonds in order of increasing ionic character in the molecules. LiF, K$_2$O, N$_2$, SO$_2$, and ClF$_3$.

• A. ClF$_3$ $<$ N_2$$< SO$_2$ $<$ K$_2$O $<$ LiF
• B. LiF $<$ K$_2$O $<$ ClF$_3$ $<$ SO$_2$ $<$ N$_2$
• C. N_2$$<SO_2$$<ClF_3$$<K$_2$O$<$LiF
• D. N_2$$<ClF_3$$<SO_2$$<K$_2$O$<$LiF

Answer 1

Answer: (C)

N_2$$<SO_2$$<ClF_3$$<K$_2$O$<$LiF

Answer 2

The order of increasing ionic character depends on the electronegativity difference between atoms, with greater differences resulting in more ionic character.