Question

Argument of $|z_{1}| = |z_{2}|$ is.

• A. $ar ⥂ ⥂ g\left( \frac{z_{1}}{z_{2}} \right) = \pi$
• B. $z_{1} + z_{2}$
• C. $0 < amp\ (z) < \pi,$
• D. $(z)$

Answer 1

Answer: (D)

$(z)$

Answer 2

Let $\Rightarrow x^{2} + y^{2} = 5$

then $x^{2} = 4 \Rightarrow x = \pm 2$

Clearly, z is in III quadrant.

Therefore argument

$y^{2} = 1$.