Question

Area under the curve $y = x^{2} - 4x$within the x-axis and the line $x = 2$, is

• A. $\frac{16}{3}sq.unit$
• B. $- \frac{16}{3}sq.unit$
• C. $\frac{4}{7}sq.unit$
• D. Cannot be calculated

Answer 1

Answer: (A)

$\frac{16}{3}sq.unit$

Answer 2

$\int_{0}^{2}{(x^{2} - 4x)dx = \left\lbrack \frac{x^{3}}{3} - \frac{4x^{2}}{2} \right\rbrack_{0}^{2} = \frac{16}{3}sq.}$unit.