Question

Area under the curve $y = \sin 2 x + \cos 2 x$ between $x = 0$ and $x = \frac { \pi } { 4 }$ is

• A. 2 sq. unit
• B. 1 sq. unit
• C. 3 sq. unit
• D. 4 sq. unit

Answer 1

Answer: (B)

1 sq. unit

Answer 2

Required area $= \int _ { 0 } ^ { \pi / 4 } ( \sin 2 x + \cos 2 x ) d x$

$= \left[ - \frac { \cos 2 x } { 2 } + \frac { \sin 2 x } { 2 } \right] _ { 0 } ^ { \pi / 4 }$

unit.