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Question

Question: Area of loop of curve y<sup>2</sup> = x(1 – x)<sup>2</sup> is :...

Area of loop of curve y2 = x(1 – x)2 is :

A

815\frac{8}{15}sq. units

B

715\frac{7}{15} sq. units

C

415\frac{4}{15} sq. units

D

None

Answer

815\frac{8}{15}sq. units

Explanation

Solution

Curve is symmetric about x – axis

Reqd. Area = 2 01x\int_{0}^{1}\sqrt{x} (1 – x) dx = 201x\int_{0}^{1}\sqrt{x} – x3/2 dx

= 2 [2x3/232x5/25]01\left[ \frac { 2 \mathrm { x } ^ { 3 / 2 } } { 3 } - \frac { 2 \mathrm { x } ^ { 5 / 2 } } { 5 } \right] _ { 0 } ^ { 1 }

= 2(2325)\left( \frac{2}{3} - \frac{2}{5} \right) = 2(10615)\left( \frac{10 - 6}{15} \right) = 8/15