Solveeit Logo

Question

Mathematics Question on Triangles

Area of a triangle formed by the line xcosα+ysinα=px \cos \alpha + y \sin \alpha = p with the coordinate axes is

A

p22sinαcosα\frac{p^2}{2 \sin \alpha \cos \alpha}

B

p2sinαcosα\frac{p^2}{ \sin \alpha \cos \alpha}

C

p2sinαcosα\frac{p}{2 \sin \alpha \cos \alpha}

D

psinαcosα\frac{p}{ \sin \alpha \cos \alpha}

Answer

p22sinαcosα\frac{p^2}{2 \sin \alpha \cos \alpha}

Explanation

Solution

The correct option is (A): p22sinαcosα\frac{p^2}{2 \sin \alpha \cos \alpha}