Question
Question: Area of a rectangle having vertices A, B, C and D with position vectors \[ - \widehat i + \dfrac{1...
Area of a rectangle having vertices A, B, C and D with position vectors
−i+21j+4k,i+21j+4k,i−21j+4k, and −i−21j+4k respectively is
(A) 21
(B) 1
(C) 2
(D) 4
Solution
This is a vector algebra based problem. We have been given with the position vectors of all four vertices of a rectangle ABCD. Here, we may involve coordinate geometry methods to find the distance between points and hence to find the area of the rectangle.
Complete step-by-step answer:
First we will find the coordinates of all four vertices with the help of their position vectors.
For vertex A,
Position vector is −i+21j+4k. So its coordinate will be (−1,21,4).
For vertex B,
Position vector is i+21j+4k. So its coordinate will be (1,21,4).
For vertex C,
Position vector is i−21j+4k.So its coordinate will be(1,−21,4).
For vertex D,
Position vector is −i−21j+4k.So its coordinate will be(−1,−21,4).
Distance formula between points (x1,y1,z1) and (x2,y2,z2) is (x1−x2)2+(y1−y2)2+(z1−z2)2
Now, we can find the length of sides of the rectangle ABCD , let us suppose AB and BC.
AB = Distance between point A and point B
=(1−(−1))2+(21−21)2+(4−4)2
=22
=2
Similarly,
BC= Distance between point B and point C
=(1−1)2+(21−(−21))2+(4−4)2
=12
=1
Area of rectangle = length of AB × length of BC
= 2×1
=2
Thus option D is correct.
Note: Vector is an object which has magnitude and direction. This problem is a good example of a geometry related question where coordinates of the points are playing an important role for the computation of other relevant terms of some given shape. Here we have used a distance formula for finding the length and breadth and hence area of the rectangle.