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Question

Mathematics Question on applications of integrals

Area lying in the first quadrant and bounded by the circle x2+y2=4 and the lines x=0 and x=2 is

A

π\pi

B

π2\frac{π}{2}

C

π3\frac{π}{3}

D

π4\frac{π}{4}

Answer

π\pi

Explanation

Solution

The correct option is(A): π\pi.

The area bounded by the circle and the lines, x=0 and x=2, in the first quadrant is

represented as

∴Area OAB=020ydx∫_0^20y dx

=024x2dx∫_0^2√4-x^2dx

=[x24x2+42sin1x2]02[\frac{x}{2}\sqrt{4-x^2}+\frac{4}{2}sin^{-1}\frac{x}{2}]_0^2

=2(π2)2(\frac{π}{2})

=π units

Thus, the correct answer is A.