Question

Area included between curves y = x² – 3x + 2 and y = – x² + 3x – 2 is -

• A. $\frac { 1 } { 6 }$sq unit
• B. $\frac { 1 } { 2 }$sq unit
• C. 1 sq unit
• D. $\frac { 1 } { 3 }$sq unit

Answer 1

Answer: (D)

$\frac { 1 } { 3 }$sq unit

Answer 2

Required area

= = $2 \left[ - \frac { x ^ { 3 } } { 3 } + 3 \cdot \frac { x ^ { 2 } } { 2 } - 2 x \right] _ { 1 } ^ { 2 }$

= $2 \left[ - \frac { 8 } { 3 } + 2 + \frac { 5 } { 6 } \right]$ = $\frac { 1 } { 3 }$ sq unit