Question

Area bounded by y = –x² + 6x – 5, y = –x² + 4x –3 and

y = 3x – 15, for x > 1, is (in sq. units)

• A. 73
• B. 13/6
• C. 73/6
• D. None of these

Answer 1

Answer: (C)

73/6

Answer 2

(

A =$\int _ { 1 } ^ { 4 } \left\{ \left( - x ^ { 2 } + 6 x - 5 \right) - \left( - x ^ { 2 } + 4 x - 3 \right) \right\} d x$ +

$\int _ { 4 } ^ { 5 } \left\{ \left( - x ^ { 2 } + 6 x - 5 \right) - ( - 3 x - 15 ) \right\} d x$A = $\frac { 73 } { 6 }$