Question

Area bounded by $y = x^3, y = 8$ and $x = 0$ is

• A. $11$ s units
• B. $14$ s units
• C. $12$ s units
• D. $6$ s units

Answer 1

Answer: (C)

$12$ s units

Answer 2

Required area $=\int_{0}^{8} x \,d y$ $=\int_{0}^{8} y^{1 / 3} d y$ $=\frac{3}{4}\left[y^{4 / 3}\right]_{0}^{8}=\frac{3}{4}\left(8^{4 / 3}\right)$ $=\frac{3}{4} \times 16=12$ sq units