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Question: Area bounded by the curve y = maxi {sinx, cosx} and x-axis , between the lines x = \(\frac { \pi } {...

Area bounded by the curve y = maxi {sinx, cosx} and x-axis , between the lines x = π4\frac { \pi } { 4 }and x = 2nis equal to

A

(421)2\frac { ( 4 \sqrt { 2 } - 1 ) } { \sqrt { 2 } }sq. units

B

(421)( 4 \sqrt { 2 } - 1 )sq. units

C

(421)2\frac { ( 4 \sqrt { 2 } - 1 ) } { 2 }sq. units

D

None of these

Answer

(421)2\frac { ( 4 \sqrt { 2 } - 1 ) } { \sqrt { 2 } }sq. units

Explanation

Solution

Bold lines represents the graph of y = maxi.{sinx, cosx}.

Required area,

Δ=π/4πsinxdxπ5π/4sinxdx\Delta = \int _ { \pi / 4 } ^ { \pi } \sin x d x - \int _ { \pi } ^ { 5 \pi / 4 } \sin x d x

=cosxπ/4π+cosxπ5π/4sinx5π/43π/2+sinx3π/22π= - \left. \cos x \right| _ { \pi / 4 } ^ { \pi } + \left. \cos x \right| _ { \pi } ^ { 5 \pi / 4 } - \left. \sin x \right| _ { 5 \pi / 4 } ^ { 3 \pi / 2 } + \left. \sin x \right| _ { 3 \pi / 2 } ^ { 2 \pi }

=(421)2= \frac { ( 4 \sqrt { 2 } - 1 ) } { \sqrt { 2 } } sq. units.