Question
Question: Area bounded by the curve \( xy=c \) and the x-axis between \( x=1 \) and \( x=4 \) , is: A. \( c\...
Area bounded by the curve xy=c and the x-axis between x=1 and x=4 , is:
A. clog3 sq. units
B. 2logc sq. units
C. 2clog2 sq. units
D. 2clog5 sq. units
Solution
The area under the function y=f(x) from x=a to x=b and the x-axis is given by the definite integral ∫abf(x) dx , for curves which are entirely on the same side of the x-axis in the given range.
If the curves are on both the sides of the x-axis, then we calculate the areas of both the sides separately and add them.
Definite integral: If ∫f(x)dx=g(x)+C , then ∫abf(x) dx=[g(x)]ab=g(b)−g(a) .
Complete step-by-step answer:
The given equation of the curve is xy=c which can also be written as y=f(x)=xc .
Using definite integrals, the area under the curve from x=1 to x=4 and the x-axis, will be given as:
A=∫14xc dx
Using ∫x1dx=logx+C , we get:
⇒ A=c[logx]14
⇒ A=c(log4−log1)
Using log1=0 and log4=log22=2log2 , we get:
⇒ A=2clog2 sq. units
The correct answer is C. 2clog2 sq. units.
Note: The graph of xy=c is a rectangular hyperbola.
In order to calculate the area of a curve from y=a to y=b and the y-axis, we will make use of ∫abf(y) dy .
The length of a curve y=f(x) from x=a to x=b is given by L=∫ab1+(dxdy)2dx .