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Question: Area bounded by the curve \( xy=c \) and the x-axis between \( x=1 \) and \( x=4 \) , is: A. \( c\...

Area bounded by the curve xy=cxy=c and the x-axis between x=1x=1 and x=4x=4 , is:
A. clog3c\log 3 sq. units
B. 2logc2\log c sq. units
C. 2clog22c\log 2 sq. units
D. 2clog52c\log 5 sq. units

Explanation

Solution

The area under the function y=f(x)y=f(x) from x=ax=a to x=bx=b and the x-axis is given by the definite integral abf(x) dx\left| \int_{a}^{b}{f}(x)\ dx \right| , for curves which are entirely on the same side of the x-axis in the given range.
If the curves are on both the sides of the x-axis, then we calculate the areas of both the sides separately and add them.
Definite integral: If f(x)dx=g(x)+C\int{f}(x)dx=g(x)+C , then abf(x) dx=[g(x)]ab=g(b)g(a)\int_{a}^{b}{f}(x)\ dx=[g(x)]_{a}^{b}=g(b)-g(a) .

Complete step-by-step answer:
The given equation of the curve is xy=cxy=c which can also be written as y=f(x)=cxy=f(x)=\dfrac{c}{x} .
Using definite integrals, the area under the curve from x=1x=1 to x=4x=4 and the x-axis, will be given as:
A=14cx dxA=\left| \int_{1}^{4}{\dfrac{c}{x}}\ dx \right|
Using 1xdx=logx+C\int{\dfrac{1}{x}dx}=\log x+C , we get:
A=c[logx]14A=c\left[ \log x \right]_{1}^{4}
A=c(log4log1)A=c(\log 4-\log 1)
Using log1=0\log 1=0 and log4=log22=2log2\log 4=\log {{2}^{2}}=2\log 2 , we get:
A=2clog2A=2c\log 2 sq. units
The correct answer is C. 2clog22c\log 2 sq. units.

Note: The graph of xy=cxy=c is a rectangular hyperbola.
In order to calculate the area of a curve from y=ay=a to y=by=b and the y-axis, we will make use of abf(y) dy\left| \int_{a}^{b}{f}(y)\ dy \right| .
The length of a curve y=f(x)y=f(x) from x=ax=a to x=bx=b is given by L=ab1+(dydx)2dxL=\int_{a}^{b}{\sqrt{1+{{\left( \dfrac{dy}{dx} \right)}^{2}}}dx} .